A jet of enemy is flying …
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Gaurav Seth 6 years, 7 months ago
Let the point (x, y) be the current position of helicopter along the curve (y = x2 + 2).
Given jet is placed at the point (3,2).
Therefore, distance between jet and soldier = D![]()
Now, we know that, if D is minimum then D2 is also minimum.
So, D2 =
For minimum D2, we have
⇒ x = 1 as there are no real rots for the equation
Again,
Clearly, for x = 1, distance is minimum.
On putting value of x in the given curve , we get
y = (1)2 + 2 = 3
Therefore, point (1,3) is nearest to point (3,2)
Hence, minimum distance =
1Thank You