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Y=logx5 then find dy/dx

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Y=logx5 then find dy/dx

    • Posted by Ajay Singh 6 years, 11 months ago

    CBSE > Class 12 > Mathematics
    • 1 answers

    Aakash Baisla 6 years, 11 months ago

    Taking log on both sides Log y =log log x5 Log y =5 log log x Diff.w.r.t.to x 1/y ×dy/dx=5/log X ×1/x+0 Dy/dx=y{5/xlogx} dy/dx=logx5{5/xlogx}

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