Find dy/dx sin{1-x2/1+x2

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Find dy/dx sin{1-x2/1+x2

Posted by Varun Nagar 6 years, 11 months ago

CBSE > Class 12 > Mathematics

1 answers

H I T E S H 6 years, 11 months ago

Y=sin(1-x2/1+x2) Let (1-x2/1-x2) =U Y=sin U dU/dx=d(1-x2/1+x2)/dx =(1+x2)(-2x)-(1-x2) (2x) /(1+x2)2. =-2x-2x3-2x+2x3/(1+x2)2 =-4x/(1+x2)2 dY/dU=cosU dY/dx=dy/du*du/dx =cos U*-4x/(1+x2)2 Putting value of U =cos(1-x2/1+x2)*-4x/ (1+x2)2

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