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A=diag[1,-2,3] B=diag[3,4,-6] C=diag[0,1,2] find 4A-2B+3C

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A=diag[1,-2,3] B=diag[3,4,-6] C=diag[0,1,2] find 4A-2B+3C

    • Posted by Shivani Gehlot 7 years, 1 month ago

    CBSE > Class 12 > Mathematics
    • 1 answers

    Randhir Prasad 7 years, 1 month ago

    4A=4 [1 -2 3] = [4 -8 12] ( 1) 2B=2 [3 4 -6] = [ 6 8 -12] (2) 3c=3 [0 1 2] [0 3 6] (3) Compute the following equation

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