Differentiate sin x^5
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Posted by Nikhil Tyagi 6 years, 11 months ago
- 2 answers
Gaurav Seth 6 years, 11 months ago
Answer:
dydx=cos(x5)⋅5x4
Explanation:
y=sinx5
Using the chain rule:
If y=y(u) and u=u(x) then, dydx=(dydu)⋅(dudx)
y=sinu
dydx=cosu
u=x5
dudx=5x4
Therefore,
dydx=(dydu)⋅(dudx)
dydx=cosu⋅5x4
Substitute u back in and rearrange:
dydx=cos(x5)⋅5x4
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Nikhil Tyagi 6 years, 11 months ago
0Thank You