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Differentiate sin x^5

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Differentiate sin x^5
  • 2 answers

Nikhil Tyagi 5 years, 2 months ago

Grt but x pwr 5

Gaurav Seth 5 years, 2 months ago

Answer:

dydx=cos(x5)⋅5x4

Explanation:

y=sinx5

Using the chain rule:

If y=y(u) and u=u(x) then, dydx=(dydu)⋅(dudx)

y=sinu
dydx=cosu

u=x5
dudx=5x4

Therefore,
dydx=(dydu)⋅(dudx)
dydx=cosu⋅5x4

Substitute u back in and rearrange:
dydx=cos(x5)⋅5x4

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