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(cosx)^2dy/dx+y=tanx please solve this differential equation …

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(cosx)^2dy/dx+y=tanx please solve this differential equation which is in the form of linear equation ???
  • 1 answers

Sumit Kumar 7 years ago

dy/dx+y/(cosx)^2=tanx/(cosx)^2 I.F= e^(integration of 1/(cosx)^2) =e^tanx So, y.e^tanx= integ.of tanx/(cosx)^2 . e^tanx dx + c y.e^tanx= e^tanx(tanx-1) + c So the differential eqn. Is -- y = tanx-1+ c(e^-tanx) Put tanx=t in integ.
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