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A and B are two mutually exclusive event of an experiment.IfP('notA')=0.65,P(AUB)=0.93 and P(B)=p.Find the value of p.

Posted by Muskan Khatter 5 years, 4 months ago

CBSE > Class 11 > Mathematics

1 answers

Mudita Jain 5 years, 4 months ago

As A and B are mutually exclusive therefore P(A intersection B) = 0 And P(A)= 1- P(not A) P(A)= 1-0.65 P(A) =0.35 Now by addition theorem, P(AUB) = P(A) +P(B) - P (A intersection B) 0.93= 0.35+ P(B)-0 P(B)= 0.58 Ans

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