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Integral of dx/1+tanx

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Integral of dx/1+tanx
  • 2 answers

Harsh Dee 7 years ago

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Harsh Dee 7 years ago

1/1+sinx/cosx == 1/cosx+sinx/cosx ==cosx/sinx+cosx Now divide and multiply by 2 == 1\2 2cosx/sinx+cosx ====1/2 cosx+cosx/sinx+cosx {break 2cosx into cosx+cosx} === now add and subtract sinx in num. === cosx+sinx+cosx-six/sinx+cosx=== now separate them and then === cosx+sinx/cosx+sinx +cosx-sinx/cosx+sinx now integrate it....
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