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Taninverseroot3-cotinverseroot4

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Taninverseroot3-cotinverseroot4

    • Posted by Vicky Singh 7 years ago

    CBSE > Class 12 > Mathematics
    • 1 answers

    Nehal Mehta 7 years ago

    Tan^-1(√3) - cot^-1(√4) = tan^-1(√3) - tan ^-1(1/√4) [tan^-1(A) - tan^-1(B) = tan^-1(A - B/ 1+AB] = tan^-1( √12 - 1/√4 - √3) = tan^-1 ( √12 -1/√4 - √3 × √4 + √3/ √4 + √3) = tan^-1 (4√3 - √4 + 6 - √3)

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