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Integration of (sinx - cosx)dx/√sin2x ?

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Integration of (sinx - cosx)dx/√sin2x ?
  • 1 answers

Aryan Singhania 7 years ago

Denominator .......√(sin2x-1)+1 Then √(cosx-sinx)^2 +1 Then take cosx-sinx =t Then apply dx÷ t^2+a^2
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