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∫tan⁻¹x/(1+x)² dx

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∫tan⁻¹x/(1+x)² dx
  • 2 answers

Shikshit Rana 7 years, 1 month ago

There is (1+x)^2 whole square. Not 1+ x^2

Vidhi Jain 7 years, 1 month ago

put tan-1 = t and then integrate......... you will get the denominator as dt
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