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Integrate (1+t^2)/(1+t^4) dt

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Integrate (1+t^2)/(1+t^4) dt
  • 1 answers

Lakshmi Kumari 7 years, 1 month ago

1+t^2/1+t^4 dt = t^2 (1/t^2+1)/t^4 (1/t^4+1) ------------1 Put y=t-1/t = y^2=(t-1/t)^2 y^2=t^2+1/t^2-2----------a Dy/dt=1+1/t^2 Dy=1+1/t^2dt -----------2 Put 2 in 1 & a in 1 =Dy/y^2+2 from eq-a = 1/root2 tan inverse(y/root2) + c after that put value of y then the answer will complete : wkt tan inversex=1/1+x^2 Plzz write it in you note book for better understand how i wrote this dont take it orally plzz write it in your noteboom and then understand this one Thank you ....
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