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Differentiate x^x^x with respect to x

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Differentiate x^x^x with respect to x
  • 1 answers

G K 7 years, 1 month ago

Let y = x^(x^x)........ Taking log both side....... logy = (x^x) logx......... Product rule lgado...... U will get..... ?dy/dx = y. x^x[(logx+1)logx + 1/x]?..... :-)
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