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integrate : upper limit =2 lower limit =1 , 1/x(1+x^2)

    • Posted by Gaurisha Trikha 7 years, 2 months ago

    CBSE > Class 12 > Mathematics
    • 1 answers

    Aditya Roy 7 years, 2 months ago

    First take x² common on denominator = 1/x•x²[(1/x²)+1] =Take [(1/x²)+1]=t Then after differentiating we got -2/x³ dx=dt Therefore -1/2Integration 1/t dt -1/2 log|t| And then simply put the value of upper limit and lower limit Hope this could help you...!

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