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if radius of the earth shrinks 2% mass remaining constant then how would the value of acceleration due to gravity change?

    • Posted by Meenal Meshram 5 years, 6 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Priya Dharshini ☺☺ 5 years, 6 months ago

    The acceleration due to gravity at the surface of earth is g = G m / R2 . The radius of eath decreases by 2 %, therefore R' = R - 0.02 R = 0.98R. Now acceleration due to gravity will be : g' = GM / ( 0.98 R )2 = 1.04 g Percentage increase in acceleration due to gravity [(g' - g )/g ] x 100 = 4 %

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