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(x-x³)⅓÷(x³)⅓

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(x-x³)⅓÷(x³)⅓

Posted by Raj Yadav 6 years, 7 months ago

CBSE > Class 11 > Mathematics

1 answers

Ilu Ahirwar 6 years, 7 months ago

{tex}(x-x^3)^{1\over 3}\over (x^3){1\over 3}{/tex}

Taking cube of both numerator and denominator, we get

{tex}(x-x^3)^3*{1\over 3} \over (x^3)^3*{1\over 3}{/tex} = {tex}(x-x^3)\over x^3{/tex}

{tex}x(1-x^2)\over x^3{/tex} = {tex}(1-x^2)\over x^2{/tex}.

2Thank You

ANSWER

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CBSE > Class 11 > Mathematics