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e^2x.sinx - find integration

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e^2x.sinx - find integration

Posted by Devvrat Upadhyay 7 years, 2 months ago

CBSE > Class 12 > Mathematics

2 answers

Komal Bhamu 7 years, 2 months ago

U can use it as identity........listen and do what i wite here.... e^ax/a^2+b^2(asinbx-bcosx) It is for e^axsinbx.........for cosine the sine get reversed in the identity and interchangeing of sine and cosine functions takes place

Dhruv G 7 years, 2 months ago

Step➡1) Let I=∫(e^2x·sinx)dx ➡2) Use ILATE, let sinx ko first and e^2x ko second. ➡3) Solve it through integration by parts. Ek baar fir se integration by parts ka use hoga. Jab ye form aa jye: I = sinx•½•e^2x−½[cosx•½•e^2x+½•∫(sinx•e^2x)dx] then u put ∫(sinx•e^2x)dx=I .................finally ⇒ I=sinx•½•e^2x−½(cosx•½•e^2x+½•I) ..........simply solve for I..... ( note- step 3 wali line me ½ common lena padega jo "∫" sign ke bahr h taki I let ho sake✌) ans- I=(2/5)•e^2x•(sinx-½•cosx)?bilkul halua q hai

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