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Square root of 3+4i

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Square root of 3+4i
  • 3 answers

Rikku Mahto 5 years, 6 months ago

Firstly squaring both side compare real and imaginary then find (a2+b2)and find the value of a and b then put in +/- (a+bi)

Anmol Yadav 5 years, 6 months ago

Let x+iy=√3+4i Squaring both side (x+iy)^2=3+4i x^2-y^2+2ixy=3+4i On comparing we get x^2-y^2=3...........(i) 2xy=4 Now (x^2-y^2)^2=(x^2)^2+(y^2)^2-2(x^2)+2(x^2)^2(y^2)^2-2(x^2)^2(y^2)^2. {We add and subtract 2(x^2)^2(y^2)^2} Substitute the value of x^2-y^2 and 2xy,we get (3)^2=[(x^2)+(y^2)]^2-(2xy)^2 [(x^2)+(y^2)]^2=25 (x^2)+(y^2)=5.......(ii) Add equation (i) and (ii) On doing so we get the value of x=2√2 Sub equation (i) and (ii) On doing so we get the value of y=√2 Now assign them in standard form i.e. x+iy=+-(2√2+√2) Its ur answer bdi mehntt krai yrr aapne

Shama Praveen 5 years, 6 months ago

That's very important question
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