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Integrate from 0 to π/2 sin2x …

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Integrate from 0 to π/2 sin2x logtanx dx please help me

Posted by Abhijeet Mehta 7 years, 2 months ago

CBSE > Class 12 > Mathematics

1 answers

Dyhhj Fyjjjh 7 years, 2 months ago

I = Int.(0 - pie/2)Sin2x.log tanx dx.............(1) = Int.Sin2[(pie/2)-x].log tan[(pie/2) - x]dx = Int.(0 - pie/2)Sin2x.log Cotx.dx............(2) By Adding (1) and (2) 2I = Int.(0 - pie/2)Sin2x.[logTanx + logCotx]dx =Int.Sin2x.log[Tanx.Cotx]dx Int.Sin2x.log1dx Since Sin(2×pie/2)=Sinpie=0 》2I=0 》I=0(solved)

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