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Integration of √sinxdx

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Integration of √sinxdx
  • 5 answers

G K 7 years, 2 months ago

No Aakash....its not correct.....let me tell u the answer....2[summation n->o to infinite {(2n)!sinx^2n+3/2} / 4^n (n!)^2 (4n+3)] +C

Akash Rounit 7 years, 2 months ago

First of all , consider t= since ,then she get dt/cosx= dxnow int root of rupon cosx ,1/cosx take out and solve she get 2/3cosx since ka power 3/2then as u written here since and root of sinx Unknown that sin2x =2sinxcosx then put finally u get sin2x/3 root of sinx Got it?????????

Tushar Jaryal 7 years, 2 months ago

Hmm..we can little bit solve it by substituting sinx as t sq. But whole is'nt possible.

G K 7 years, 2 months ago

Its not in syllabus......iska ans ajib sa h......

Yash Gupta 7 years, 2 months ago

-cosx + c
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