Is 51 tearm of the AP …
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Yogita Ingle 5 years, 7 months ago
Here the first term; a = 5
Common difference; d = 11 - 8 = 8 - 5 = 3
So, nth term is given by;
tn = a + (n − 1)d = 5 + (n − 1) × 3
Now to prove whether 51 is term of this A.P, taking tn = 51
51 = 5 + (n − 1) × 3
⇒ 51 = 5 + 3n − 3
⇒ 3n = 51 + 3 − 5
⇒ 3n = 49
n = 49/33
Now we know that number of terms can't be in fraction.
So, 51 is not term of this A.P.
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