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Integration of (1+ log x)^2/x

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Integration of (1+ log x)^2/x
  • 1 answers

Dhruv G 7 years, 3 months ago

Soln: Put 1+logx= t Differentiate on both sides wrt x, 1/x•dx=dt So int(1+logx)^2/x•dx becomes, int(t^2•dt)= t^3/3=1/3(1+logx)^3 Your final ans: 1/3(1+logx)^3 + C
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