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intregrate 1/1-tanx

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intregrate 1/1-tanx
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Sajid Khan 7 years, 3 months ago

tanx ko sinx and cosx me change karo [cosx/cosx-sinx] milega fir arrange karo =1/2[(cosx-sinx)+(cosx+sinx)/(cosx-sinx) doosre ka square =1/2[1dx]+1/2[(cosx+sinx)^2/cos^2x-sin^2x]= x/2+1/2[1+sin2x/cos2x] =x/2+1/2[1/cos2x+sin2x/cos2x] =x/2+1/2[sec2x+tan2x] =x/2+1/4log(secx+tanx)+1/4log(secx)+c i hope understand you
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