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Diffrentiate (logx)^x+(x^logx)

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Diffrentiate (logx)^x+(x^logx)
  • 2 answers

Mohd Ashar Khan 7 years, 4 months ago

Sorry ye last me 2logx/2 ki jgha 2logx/x aega

Mohd Ashar Khan 7 years, 4 months ago

(logx)^x(1/logx+log(logx))+x^logx(2logx/2)
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