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2sin68°/cos22°-2cot15°/5tan75°-(3tan45°tan20°tan40°tan50°tan70°)/5

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2sin68°/cos22°-2cot15°/5tan75°-(3tan45°tan20°tan40°tan50°tan70°)/5

Posted by Ritesh Barnwal 5 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Ritu Sena 2 years, 11 months ago

2sin(90°-22°)/cos22°-2cot(90°-75°)/5tan75°-(3tan45°tan20°tan40°tan50°tan70°)/5 = 2cos22°/cos22°- 2tan75°/5tan75°- 3/5 = 2-2/5-3/5 = 8/5-3/5 = 5/5=1

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CBSE > Class 10 > Mathematics