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Let R be the relation on …

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Let R be the relation on R , defined by R={a,b: a^2+b^2=1}.show that R is the symmetric but neither reflexive nor transitive

Posted by Aishwarya Arun Kumar 7 years, 7 months ago

CBSE > Class 12 > Mathematics

1 answers

Varun Bhardwaj 7 years, 7 months ago

R ={a,b:a²+b²=1 } a²+b²=1 if a²=b² So a²+a²=1 , 2a²=1, a²=1/2 which is not belong to R so it is not reflixive a²+b²=1 b²+a²=1 when R={b,a: b²+a²=1} So R{a,b:a²+b²=1}=R{b,a:b²+a²=1 } so it is symmetric a²+b²=1 c²+b² =1 by replacing a with c a²-+b²-c²-b²=1-1 a² - c²=0 which is not belong to R so it isn't transitive

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