sqrt(6-x)+sqrt(x-10)>0
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Posted by Pranjal Sarkar 7 years, 7 months ago
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Ayaaz Ansari 7 years, 7 months ago
sqrt(6-x) + sqrt(x-10) >0
on squaring....
6-x + x-10 +2[sqrt(6x-60-x2+10x)] >0 (x2=square(x))
-16 +2 sqrt(-x2+16x-60)>0
on solving this equation.......we can get the answer i.e.
(x-6)(-x+10)>sqr(8)
(x-6)(-x+10)>64
u can easily solve this.........
0Thank You