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sqrt(6-x)+sqrt(x-10)>0

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sqrt(6-x)+sqrt(x-10)>0
  • 1 answers

Ayaaz Ansari 5 years, 11 months ago

sqrt(6-x) + sqrt(x-10) >0

on squaring....

6-x  +  x-10  +2[sqrt(6x-60-x2+10x)] >0                         (x2=square(x))

-16 +2 sqrt(-x2+16x-60)>0

on solving this equation.......we can get the answer i.e.

(x-6)(-x+10)>sqr(8)

(x-6)(-x+10)>64

u can easily solve this.........

 

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