find the derivative of sin2x
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Neeraj Sharma 7 years, 1 month ago
{tex}let\,y = \sin 2x{/tex}
{tex}differentiating\,with\,respect\,to\,x{/tex}
{tex}{{dy} \over {dx}} = {d \over {dx}}\left( {\sin 2x} \right){/tex}
{tex} = \cos 2x{d \over {dx}}\left( {2x} \right){/tex}
{tex} = 2\cos 2x{/tex}
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