let f:r-r be a function given …
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Neeraj Sharma 7 years, 1 month ago
{tex}let\,{f^{ - 1}}\left( {27} \right) = x{/tex}
{tex} \Rightarrow f\left( x \right) = 27{/tex}
{tex} \Rightarrow {x^2} + 2 = 27{/tex}
{tex} \Rightarrow {x^2} = 25{/tex}
{tex} \Rightarrow x = \pm 5{/tex}
{tex}Hence{/tex}
{tex}{f^{ - 1}}\left( {27} \right) = \left\{ { - 5,5} \right\}{/tex}
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