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How can x^2+y^2=8x will become (x-4)^2+y^2=16

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How can x^2+y^2=8x will become (x-4)^2+y^2=16
  • 2 answers

Mansi Prajapati 7 years, 8 months ago

x^2-8x+y^2=0 Add 4^2=16 on both sides (x^2- 8x+16) +y^2=16 It can be written as (x-4)^2+y^2=16

Shubh Mehrotra 7 years, 8 months ago

Completing the square method
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