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integration of logx / (logx +1)² …

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integration of logx / (logx +1)² dx

    • Posted by Raman Singhal 7 years, 8 months ago

    CBSE > Class 12 > Mathematics
    • 1 answers

    Harsh Chougale 7 years, 8 months ago

    Put (logx+1)=t logx= t-1 x= e^(t-1) dx= e^(t-1)dt Now Integration of (t-1) e^(t-1)dt / t^2 e [ e^t ( 1 / t - 1 / t^2 ) ]dt e [ e^t x 1/t ] + c e [ e^(logx+1) x 1 / (logx+1) ] + c

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