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Find the equation of the tangent …

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Find the equation of the tangent to the curve y=(x-7)÷(x-2)×(x-3) at the point where it cuts the x axis

Posted by Krishnaprasad A 7 years, 8 months ago

CBSE > Class 12 > Mathematics

2 answers

Kriti Sagar 7 years, 8 months ago

From qn we get that the tangent cuts x axis hence it's y coordinate is 0 put y=0 in eqn we will get x=7 now differentiate the eqn and put value of x nd y after differentiation, nd u will get the slope of tangent now apply y-y'=dy/dx(x-x') at point (7,0) it will be the eqn of tangent

Naitik Yadav 7 years, 8 months ago

First of all find :- dy/dx Then put dy/dx=0

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