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√cotx+√tanx_dx

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√cotx+√tanx_dx

    • Posted by Bhawna Goyal 7 years, 8 months ago

    CBSE > Class 12 > Mathematics
    • 6 answers

    K Gopika 7 years, 8 months ago

    Answer is √2sin^-1(sinxcosx - coax) + C

    1Thank You

    K Gopika 7 years, 8 months ago

    So square on both sides for the equation sin - cos =t . Last hand side it you'll get 1- 2sinxcosx with this obtain for sinxcosx in terms of t. Substitute in the integration. You'll find the answer

    1Thank You

    K Gopika 7 years, 8 months ago

    Take sin -cos as t. If you differentiate this you will get the numerator. So you should bring the denominator to this form.

    0Thank You

    K Gopika 7 years, 8 months ago

    Cross multiply it. You will get cos + sin by root of sin + cos

    1Thank You

    K Gopika 7 years, 8 months ago

    Bring cot and tan to sin and cos form

    1Thank You

    K Gopika 7 years, 8 months ago

    Dude

    0Thank You

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