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IMPORTANT MATHS FORMULAE FOR CLASS X …

CBSE, JEE, NEET, CUET

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IMPORTANT MATHS FORMULAE FOR CLASS X BOARD EXAM 2018 IGNORE MAAT KARNA DUM KE PADH KE JANA 28 TARIKH KO MATH EXAM HE BEST OF LUCK TO ALL MY FRIENDS. Algebra: (a + b)2 = a2 + 2ab + b2 (a – b)2 = a2 – 2ab + b2 (a + b) (a – b) = a2 – b2 (x + a)(x + b) = x2 + (a + b)x + ab (x + a)(x – b) = x2 + (a – b)x – ab (x – a)(x + b) = x2 + (b – a)x – ab (x – a)(x – b) = x2 – (a + b)x + ab (a + b)3 = a3 + b3 + 3ab(a + b) (a – b)3 = a3 – b3 – 3ab(a – b) (x + y + z) 2 = x2 + y2 + z2 + 2xy + 2yz + 2xz (x + y – z) 2 = x2 + y2 + z2 + 2xy – 2yz – 2xz (x – y + z)2 = x2 + y2 + z2 – 2xy – 2yz + 2xz (x – y – z)2 = x2 + y2 + z2 – 2xy + 2yz – 2xz x3 + y3 + z3 – 3xyz = (x + y + z)(x2 + y2 + z2 – xy – yz -xz) x2 + y2 = 1212 [(x + y)2 + (x – y)2] (x + a) (x + b) (x + c) = x3 + (a + b +c)x2 + (ab + bc + ca)x + abc x3 + y3 = (x + y) (x2 – xy + y2) x3 – y3 = (x – y) (x2 + xy + y2) x2 + y2 + z2 -xy – yz – zx = 1212 [(x-y)2 + (y-z)2 + (z-x)2] Linear Equation: Linear equation in one variable ax + b = 0, x = – −ba−ba Quadratic Equation: ax2 + bx + c = 0 x = −b±b2−4ac√2a−b±b2−4ac2a Discriminant D = b2 – 4ac Trial and error method In step 2 : take a product of ‘ Common terms’ as their HCF. In step3 : Take the product of All the terms, Omit the HCF value which gives you the value of LCM. Product of LCM* HCF=Product of the two polynomials Note: If cubical expression is given, it may be factorized by using ‘trial and error’ method. Remainder theorem: If (x-2) is a factor of the given expression, then take x-2 = 0 , therefore x = 2 , then substitute this value in p(x) = 5 x*x + 3 x-6 P(2) : 5(2*2) + 3(2)-6 =0 (here taking = 0 is very important. If not taken, answer can’t be found) If (x-2) leaves a remainder of 4 P(2) : 5(2*2) + 3 (2)-6 =4 ( Here taking = 4 is very important. If not taken, answer can’t be found) Linear equations in two variables If pair of linear equation is : a1 + b1y +c1 =0 and a2x + b2 y + c2=0 Then nature of roots/zeroes/solutions : i. If a1/a2 is not equal to b1/b2 then, system has unique solution, is consistent OR graph is two intersecting lines ii. If a1/a2 = b1/b2 is not equal to c1/c2 , then system has no solution, is inconsistent OR graph is parallel lines. iii. If a1/a2=b1/b2=c1/c2, then system has infinite solution, is consistent OR graph are coincident lines. Quadratic Equations Note: To find the value of ‘x’ you may adopt either ‘splitting the middle term’ or ‘formula method’. X=( -b +-(D)^.5)/2a (where D= b*b – 4ac) Hence x= (-b+- (b*b- 4ac)^.5)/2a Sum of the roots = -b/a & Product of roots= c/a If roots of an equation are given, then : Quadratic equation : x*x – (Sum of roots).x + (product of the roots) =0 If Discriminant > 0, then the roots are Real & unequal or unique, lines are intersecting. Discriminant = 0, then the roots are real & equal , lines are coincident. Discriminant< 0 , then the roots are imaginary (not real), parallel lines Triangles: If two triangles are similar then, ratio of their sides are equal. i.e if triangle ABC~ triangle PQR then AB/PQ = BC/QR = AC/PR If triangle ABC ~ triangle PQR then (Area of triangle ABC)/ Area of triangle PQR) = (side*side) /(side*side) = ( AB*AB) /( PQ*PQ) =( BC*BC)/( QR*QR) = (AC*AC)/ (PR*PR) Trigonometry: Wherever ‘square’ appears think of using the identities sin^2(x) + cos^2(x) = 1 tan^2(x) + 1 = sec^2(x) cot^2(x) + 1 = csc^2(x) tan(x+ y) = (tan x +tan y) / (1 – tan x tan y) sin(2x) = 2 sin x cos x cos(2x) = cos^2(x) – sin^2(x) = 2 cos^2(x) – 1 = 1 – 2 sin^2(x) tan(2x) = 2 tan(x) and many more are there if u want then I will send u an URL thank-you best of luck?????????
  • 4 answers

Sadhvi Deshpande 6 years, 9 months ago

Good luck

Sadhvi Deshpande 6 years, 9 months ago

Wow thanks a lot

Monika Rawat 6 years, 9 months ago

Thanks

Nimesh Chauhan 6 years, 9 months ago

Thakyou and aapko bhi good luck
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