No products in the cart.

Prove that sin^2 18°+cos^² 36°=3/4

CBSE, JEE, NEET, CUET

CBSE, JEE, NEET, CUET

Question Bank, Mock Tests, Exam Papers

NCERT Solutions, Sample Papers, Notes, Videos

Prove that sin^2 18°+cos^² 36°=3/4
  • 3 answers

Rohan Gupta 6 years, 8 months ago

We can also do this without actually knowing the values

Saloni Kumari 6 years, 8 months ago

sin18°=√5-1/4 & cos36°=√5+1/4 putting this values above we get (√5-1/4)^2+(√5+1/4)^2=3/4

Saloni Kumari 6 years, 8 months ago

sin18°=√5_1/4 & cos36°=√5+1/4 putting this values above we get (√5-1/4)^2+(√5+1/4)^2 =3/4
http://mycbseguide.com/examin8/

Related Questions

Square of 169
  • 1 answers
Find the product. (4x²) (–5³)
  • 0 answers
Express the complex number i-39
  • 0 answers
2nC2:nC3=33:10
  • 0 answers
Ch 1 ke questions
  • 1 answers
(3+i)x + (1-2i) y +7i =0
  • 1 answers

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Test Generator

Test Generator

Create papers online. It's FREE.

CUET Mock Tests

CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

Download myCBSEguide App