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[Cu(Cl)4]-2 ka hybridization?no.of unpaired electron? Isme …

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[Cu(Cl)4]-2 ka hybridization?no.of unpaired electron? Isme last electron jump nhi krega na..
  • 2 answers

Vishal Chaudhary 6 years, 9 months ago

Sp^3 1 no

Ruby Bajwa 6 years, 9 months ago

Hybridization: sp3 No. Of unpaired electrons=1 As Cl is a weak field ligand therefore no pairing against Hund's rule.
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