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{tex}[i^{18}+(1/i)^{25}]^3{/tex}

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{tex}[i^{18}+(1/i)^{25}]^3{/tex}

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H S 8 years, 3 months ago

={(i^2)^9-[(i)^2]^12.i}^3 =[-i-(-1)^12.i]^3 =(-i-i)^3 =(-2i)^3 =-8(i^3) =8i
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