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{tex}[i^{18}+(1/i)^{25}]^3{/tex}

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^{{tex}[i^{18}+(1/i)^{25}]^3{/tex}}

Posted by Kanhaiya Kumar Singh 6 years, 7 months ago

CBSE > Class 11 > Mathematics

1 answers

H S 6 years, 7 months ago

={(i^2)^9-[(i)^2]^12.i}^3 =[-i-(-1)^12.i]^3 =(-i-i)^3 =(-2i)^3 =-8(i^3) =8i

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