One says give me a hundred …
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Sia ? 5 years, 6 months ago
Let the amount of their respective capitals be x and y.
{tex}\therefore{/tex} According to the given condition,
x + 100 = 2(y - 100)
or, x + 100 = 2y - 200
or, x - 2y= - 300 ........(i)
and 6(x - 10) = y + 10
or, 6x - 60 = y + 10
{tex} \Rightarrow {/tex} 6x-y=70 .......(ii)
On multiplying eqn. (ii) by 2 and subtracting from eqn. (1),
{tex}\therefore{/tex}
On substituting x = 40 in eqn. (1),
40 - 2y = - 300
or, 2y = 340
{tex}\therefore{/tex} y = 170
Hence, the amount of their respective capitals are 40 and 170.
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