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From a window, h metres high …

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From a window, h metres high above the ground, of a house in a street, the angles of elevation and depression of the top and the foot of another house on the opposite side of the street are α and β respectively. Show that the height of the opposite house is h(1+tanα.cotβ) metres.
  • 10 answers
Oo but nice

Darpan Yadav 6 years, 9 months ago

Coincidently, I had solved this question , today
Very nice samaira???

Nancy Rajput 6 years, 9 months ago

thanks
How

Darpan Yadav 6 years, 9 months ago

Let WB = h m, height of the smaller window & QO = H m, height of the other window. Let BO = x m, distance between the two windows. ∠QWM = α & ∠WOB = β In ∆WOB, In ∆QWM, Comparing eq. 1 and eq. 2, we get (H – h)/tan α = h/tan β ⇒ (H – h) tan β = h tan α ⇒ H tan β – h tan β = h tan α ⇒ H tan β = h tan α +h tan β ⇒ H tan β = h (tan α + tan β) ⇒ H = (h (tan α + tan β))/tan β ⇒ H = h (tan α/tan β + 1) ⇒ H = h (1+tan α/tan β) ⇒ H = h (1+tan α cot β) Hence, proved.

Nancy Rajput 6 years, 9 months ago

send to me
Have solved

Nancy Rajput 6 years, 9 months ago

so solve it
Very simple ...but can't be done here sorry
http://mycbseguide.com/examin8/

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