A toy is in the form …
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Sia ? 5 years, 6 months ago
According to question it is given that
Diameter of the base of the cone is = 7cm
Therefore radius = {tex}\frac{7}{2}{/tex} = 3.5cm
Total height of the toy = 14.5 cm
Height of the cone = 15.5 - 3.5 = 12 cm
Height of the hemisphere = 3.5 cm
According to question it is also given that
Volume of the toy = Volume of cone + Volume of hemisphere
={tex}\frac{1}{3} \pi r^2h + \frac{2}{3} \pi r^2{/tex}
={tex}\frac{1}{3}πr^2(2r+h){/tex}
={tex}\frac{1}{3}×\frac{22}{7}×(3.5)^2[2×3.5+12]{/tex}
={tex}\frac{1}{3}×22×1.75×19{/tex}
= {tex}{/tex}243.83 cm{tex}^3{/tex}
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