Solve for x √3x^2-2√x-2√3=0
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Posted by Prashant Patel 5 years, 6 months ago
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Sia ? 5 years, 6 months ago
{tex}\sqrt { 3 } x ^ { 2 } - 2 \sqrt { 2 } x - 2 \sqrt { 3 } = 0{/tex}
{tex}\sqrt { 3 } x ^ { 2 } - 3 \sqrt { 2 } x + \sqrt { 2 } x - 2 \sqrt { 3 } = 0{/tex}
{tex}\sqrt { 3 } x [ x - \sqrt { 6 } ] + \sqrt { 2 } [ x - \sqrt { 6 } ] = 0{/tex}
or, {tex}( x - \sqrt { 6 } ) ( \sqrt { 3 } x + \sqrt { 2 } ) = 0{/tex}
or, {tex}x = \sqrt { 6 } , - \sqrt { \frac { 2 } { 3 } }{/tex}
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