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When light of wavelength 400nm incident …

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When light of wavelength 400nm incident on the cathode of a photo cell, The stopping potential is recorded 6v . If the wavelength of light is increased to 600 nm , calculate the new stopping potential .

Posted by Srishty Saini 6 years, 9 months ago

CBSE > Class 12 > Physics

1 answers

Yuthika Yadav 6 years, 9 months ago

eV°1 = hc/lambda1 -W° -------------------------------- eq. 1. eV° 2 =hc/lambda2 -W° ------ eq2. Now substraction eq.2 from eq1 you will get. e(V°1 - V°2 )= hc(1/lambda1- 1/lambda 2) V°1 = 6 V .......... lambda 1 = 400nm and lambda2 = 600nm. . e= 1.6 ×10^-19 . Solve for V° 2

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