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Find the volume of a solid …

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Find the volume of a solid in the form of a right circular cylinder with hemisphere ends, whose total height is 2.7m and the diameter of each hemispherical end is 0.7m.
  • 1 answers

Sia ? 5 years, 4 months ago

Diameter of common base = 0.7m
Radius of common base = {tex}\frac{0.7}{2}{/tex}m
Total height of solid = 2.7m
Height of cylinder = 2.7 - {tex}\frac{0.7}{2}{/tex} - {tex}\frac{0.7}{2}{/tex} = 2 m
{tex}\therefore{/tex} Volume of solid = volume of cylinder + 2 {tex}\times{/tex}volume of hemisphere
{tex}= \pi r ^ { 2 } h + 2 \times \frac { 2 } { 3 } \pi r ^ { 3 }{/tex}
{tex}= \frac { 22 } { 7 } \times \frac { 0.7 } { 2 } \times \frac { 0.7 } { 2 } \times 2 + 2 \times \frac { 2 } { 3 } \times \frac { 22 } { 7 } \times \frac { 0.7 } { 2 } \times \frac { 0.7 } { 2 } \times \frac { 0.7 } { 2 }{/tex}
{tex}= \frac { 22 } { 7 } \times \frac { 0.7 } { 2 } \times \frac { 0.7 } { 2 } \times 2 \left[ 1 + \frac { 2 } { 3 } \times \frac { 0.7 } { 2 } \right]{/tex}
{tex}= \frac { 22 } { 7 } \times \frac { 0.7 } { 2 } \times \frac { 0.7 } { 2 } \times 2 \times \frac { 3.7 } { 3 }{/tex}
=0.949 m3 
=0.95 m3 (approx.)

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