what is the ratio of areas …
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Sia ? 5 years, 5 months ago
Let radius of circle be r cm
Its area = {tex}\pi{/tex}r2 sq units
Side of an equilateral triangle = diameter of the circle = 2r
Area of the equilateral triangle
{tex}= \frac { \sqrt { 3 } } { 4 } \times ( 2 r ) ^ { 2 }{/tex}
{tex}= \frac { \sqrt { 3 } } { 4 } \times 4 r ^ { 2 } = \sqrt { 3 } r ^ { 2 }{/tex}
{tex}\frac { \text { Area of the circle } } { \text { Area of the triangle } } = \frac { \pi r ^ { 2 } } { \sqrt { 3 } r ^ { 2 } } = \frac { \pi } { \sqrt { 3 } }{/tex}
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