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Find the equation of the tangent …

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Find the equation of the tangent and normal to the curve x3+y3=6xy at point (3,3)

Posted by Yuvan Prabhu 7 years, 9 months ago

CBSE > Class 12 > Mathematics

1 answers

Vishisht Saxena 7 years, 9 months ago

Given:- (x1, y1) = (3,3). &. 3x + 3y = 6xy. => 3 ( x + y ) = 3 × 2 × xy => x + y = 2xy. Differentiate it w.r.t. x, we get,. 1+ (dy/dx) = 2y + 2x(dy/dx). =>. {2x - 1}.(dy/dx) = 1 - 2y. => (dy/dx) = (-){2y-1}/{2x-1}. Now, using point-slope eqπ form, we have,. (y - y,) = (dy/dx).(x - x,). Now, just put the values and solved it...? ??

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