A circuit has fuse of 5A. …
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Shweta Gulati 7 years, 2 months ago
Suppose x number of such bulbs can be used
Power of one bulb = 100 watt
Power of x bulbs (p) = 100 X x watts
Potential difference (V) = 220 volts
I = 5 ampere
We know that P = VI
100 X x = 220 x 5
x = 220 x 5 /100 = 11 bulbs.
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