sinX+cosX ÷ whole root (1+sin2X)dx integrate
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Posted by Lav Sharma 8 years, 3 months ago
- 3 answers
Sunil Yadav 8 years, 3 months ago
Naveen Sharma 8 years, 3 months ago
{tex}\int {sin x+ cos x\over \sqrt {1+sin2x}}dx{/tex}
{tex}=> \int {sin x+ cos x\over \sqrt {sin^2x+cos^2x+2sinxcosx}}dx{/tex}
{tex}=> \int {sin x+ cos x\over \sqrt {(sinx+cosx)^2}}dx{/tex}
{tex}=> \int {sin x+ cos x\over {sinx+cosx}}dx{/tex}
{tex}=> \int dx = x + C{/tex}
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Taruna Dagar 8 years, 3 months ago
0Thank You